Hi everyone.
I was running the growth of ice on a substrate surface (graphene). I found it so different between using two T-coupling groups and using one T-couping group.
When I set the substrate and ice as two independent T-coupling groups, the bottom layer of ice (the layer in contact with substrate) is hard to maintain its original crystal, or to say the bottom layer of ice melts quickly.
The substrate is set to be frozen in these two cases
freezegrps = non-water
freezedim = Y Y Y
I want the bottom layer of ice to maintain its crystal structure, but I am not sure which one is correct? And what makes it so diffenet when seperate it into two T-coupling groups?
Thank you so much! I will really appreciate it if you can do me this favor!
nrdf stands for number of degrees of freedom. I would expect the number to be approximately the same, but they clearly are not. I suppose the number of degrees of freedom is too high when using two groups. Are the T-coupling groups really the only thing you changed between the two setups?
My last answer was incorrect. The seem to be two issues with counting the number of degrees of freedom. One with frozen atoms and constraints and another one with frozen atoms being in the same group as non-frozen atoms.
The only way I can get correct counts for my test system is when using two separate T-coupling groups and removing all constraints between frozen atoms.
No freeze substrate, it seems to be normal. The nrdf 111134 and 37821+73314 are almost the same. When freeze substrate, 19206.8 =! 37821+0. But two T groups one should be right because it is 37821, as the same when no freeze.
I think there is something wrong when there are freezon atoms in one T group.
Yes. I found the issue and have a fix. The issue appears when fully frozen atoms are in the same T-coupling group as the non-frozen atoms. Using two temperature coupling groups avoids this issue.
It seems that constraints do not affect this at all. My previous comment on that was incorrect.