GROMACS version: 2025.2
GROMACS modification: No
Hi
I would like to try out the deform mdp command to calculate the viscosity of an isotropic liquid (just water as a model system for now) but I am at a loss when it comes to some details. When I start with a rectangular box, and put in my mdp file, e.g.:
deform 0 0 0 0 0 0.005
I understand this means that i exert shear along the c(y) component of the box (which, i belive, is the y-component of the box-vector that originally points in the z-direction). As discussed in a previous post by MichelePellegrino and mattiafelicepalermo I then get the viscosity by dividing the off diagonal stress tensor by the corresponding shear rate. three questions:
- with the deform command above, which element of the stress tensor (PXX, PXY, …) and which box dimension (together with the deform rate (here 0.005) to get the shear rate) would i then use, to get the viscosity?
- with deform, do i want to use a non-cubic initial box to improve convergence? if so, which box dimension would I elongate here?
- In the documentation it is mentioned that deform can be combined with anisotropic or semi-isotropic pressure scaling. For an isotropic liquid such as bulk water this would make no sense, and I just use normal isotropic pressure scaling, correct?
thanks for any advice!
michael